Mileage Formula: Definition, Average Speed, Time Measurement and Example Problems

August 08, 2023
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Mileage Formula: Definition, Average Speed, Time Measurement and Example Problems – How to measure mileage with the formula? On this occasion About the knowledge.co.id will discuss it, including the measurement of time and of course other things that also cover it. Let's look at the discussion together in the article below to better understand it

Mileage Formula: Definition, Average Speed, Time Measurement and Example Problems

Moving objects have speed. Speed is the distance traveled by a moving object per unit time. Speed can have various units, for example kilometers per hour (km/hour), miles/hour, meters per minute (m/minute), meters per second (m/second), centimeters per second (cm/second) and so on.

The driver of the car drives at high speed on the highway, but when on a busy city road he will drive the car slowly according to the road conditions. Therefore in physics, there is a distinction between constant speed and average speed.

Measuring the distance traveled, travel time, and average speed can be done with the kinematics physics formula, namely the formula for measuring uniform straight motion (glb). The following is the discussion:

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Kinematics is a branch of physics that studies motion regardless of the causes of motion. Regarding the causes of motion will be discussed in Dynamics.

The motion discussed in this section is the motion experienced by objects on a straight line trajectory (call it a highway).

Uniform straight motion means that this movement has a fixed object speed indicator, Fixed means it doesn't change (from start to finish the speed of the object does not change) and in this case we modify it as the average speed vehicle.

Speed is defined as the change in position per unit time.

Uniform Straight Motion (GLB) is a straight line motion that has a constant velocity. Then the acceleration value is a = 0. GLB movement is linear and the value of the speed is the result of the distance divided by the time traveled.

Formula:

$\!v\frac{s}{t}$

Under the condition:

$\!s$ = distance traveled (m, km)
$\!v$ = Speed (km/h, m/s)
$\!t$ = Travel time (hours, seconds)

Notes:

To find the distance traveled, the formula is $\!s\!v\times\!t$ .
To find the travel time, the formula is $\!t\frac{s}{v}$ .
To find speed, the formula is $\!v\frac{s}{t}$ .

Average speed

Formula:

$\!v\frac{s_{total}}{t_{total}} \frac {V_{1} \times t_{1} + V_{2} \times t_{2} +... + V_{n} \times t_{n}} {t_{1} + t_{2} +... + t_{n}}$

Distance Measured

Komeng drives a car with an average speed of 60 km/hour. He departed from the city
Jakarta to the city of Bandung at 04.00. If he arrives in the city of Bandung at 07.00
How many kilometers has Rizky traveled?
Answer :
Mileage formula $\!s\!v\times\!t$

Time taken = time arrived – time left
= 07.00 – 04.00
= 3 hours

Distance traveled = speed X time
= 60 km/hour X 3 hours
= 180 km
So Komeng has covered a distance of 180 km, namely from Jakarta to Bandung.

Measurement of Time Traveled

The distance from Jakarta to Bogor is 60 km. Rossi left for Bogor on a motorcycle at 07.30.
Average speed 40 km/h.
a. How long does it take Rossi to get to Bogor?
b. What time did Rossi arrive in Bogor?

Answer :
a. The formula for calculating travel time = $\!t\frac{s}{v}$ or

= distance: speed
= 60 km: 40 km/h
= 1.5 hours
So Rossi needs time to cover the distance from Jakarta to Bogor
1.5 hours = 1 hour 30 minutes.

b. Rossi arrives in Bogor = Departure time + travel time
= hit ~~07.00~~07.30+ at 01.30
= ~~08.30~~09.00
So Rossi arrived in Bogor at ~~08.30~~09.00.

Average Speed Measurement

The distance from the city of Purwokerto to Cilacap is 80 Km. Saprol drove away
from Purwokerto at 06.00 and arrived in Cilacap at 08.00. What is the average speed
Saprol drives a car?

Answer :
Before we calculate the average speed we must determine the time taken
by Saprol namely = Arrive – depart
= 08.00 – 06.00
= 2 hours
So the time used by Saprol is 2 hours.

Then we determine the average speed of Saprol driving a car.

Average speed formula = $\!v\frac{s_{total}}{t_{total}} \frac {V_{1} \times t_{1} + V_{2} \times t_{2} +... + V_{n} \times t_{n}} {t_{1} + t_{2} +... + t_{n}}$ or

= distance: travel time
= 80 km: 2 hours
= 40 km/hour
So Saprol drives the car at an average speed of 40 km/h.

Problems example

Problem 1
Problem: A train goes from station A to station B with an average speed of 45 km/hour. The time taken from station A to station B is 24 minutes. What is the distance between station A and station B?
Answer:
district average = 45 km/hour = (45 km)/ (60 minutes) = 0.75 km/minute
Travel time = 24 minutes
Mileage = (kec-average2) x (travel time) = 0.75 x 24 = 18 km
So the distance between station A and station B is 18 km

Problem 2
The distance between city A to city B is 90 km. This distance can be reached by a car for 1 1/2 hours. What is the average speed of the car in km/h?

Answer
To find the average speed, use the magic triangle formula as below.
Given distance = 90 km
Time = 1 1/2 hours (1.5 hours)
Speed asked?

K=J: W
K = 90 km: 1 1/2 (3/2) hours = 90 x 2/3 (division must be reversed) or
K = 90 km: 1.5 hours
K = 60 km/hour
So average speed = 60 km/hour

Mileage Formula: Definition, Average Speed, Time Measurement and Example Problems

Problem 3
Problem: A motorboat is moving in a straight line with an average speed of 15 km/hour. How many kilometers will the boat cover in 25 minutes?
Answer:
district average = 15 km/hour = (15 km)/ (60 minutes) = 0.25 km/minute
Travel time = 25 minutes
Distance = (kec-average2) x (travel time) = 0.25 x 25 = 6.25 km
So the distance traveled by the motor boat is 6.25 km

Problem 4
Problem: A bee can fly with an average speed of 60 m/min. How many meters can the bee cover in 15 seconds?
Answer:
district average2 = 60 m/min = (60 m)/ (60 sec) = 1 m/s
Travel time = 15 seconds
Distance = (kec-average2) x (travel time) = 1 x 15 = 15 m
So the distance traveled by the bee is 15 m

Problem 5
Problem: An ant is walking down a stretch of rope at an average speed of 1.2 meters per minute. How many inches does the ant cover in 45 seconds?
Answer:
district average = 1.2 m/min = (1.2 x 100 cm)/ (60 seconds) = 120/60 = 2 cm/second
Travel time = 45 seconds
Distance traveled = (kec-average2) x (travel time) = 2 x 45 = 90 cm
So the distance traveled by the ant is 90 cm

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Mileage Formula: Definition, Average Speed, Time Measurement and Example Problems